The speed (v) of a particle moving in a circle of radius R varies with distance s as v=ks where k is a positive constant.Calculate the total acceleration of the particle

The kinetic energy K of a particle moving along a circle of radius R depends upon the distance S as K=betaS^2 , where beta is a constant. Tangential acceleration of the particle is proportional to

The linear speed of a particle moving in a circle of radius R varies with time as v = v_0 - kt , where k is a positive constant. At what time the magnitudes of angular velocity and angular acceleration will be equal ?

A particle moves in a circular path such that its speed 1v varies with distance s as v = sqrt(s) , where prop is a positive constant. Find the acceleration of the particle after traversing a distance s .

A particle moves in a circular path such that its speed v varies with distance s as v=alphasqrt(s) where alpha is a positive constant. If the acceleration of the particle after traversing a distance s is [alpha^2sqrt(x+s^2/R^2)] find x.

The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as T = KS2 where K is a constant. Find the force acting on the particle as a function of S -

The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as K=lambdas^(2) , where lambda is a constant. Find the force acting on the particle as a function of s .

The speed of a particle moving in a circle of radius r=2m varies witht time t as v=t^(2) , where t is in second and v in m//s . Find the radial, tangential and net acceleration at t=2s .

The acceleration of an object moving in a circle of radius R with uniform speed v is

A particle of mass m moves in a circle of radius R in such a way that its speed (v) varies with distance (s) as v = a sqrt(s) where a is a constant. Calcualte the acceleration and force on the particle.

A particle is moving in a circle of radius 1 m with speed varying with time as v=(2t)m//s . In first 2 s