Calculate the half-life period of a radioactive element which remains only 1/16 of it's original amount in 4740 years.
( A) 1185 years
( B) 2370 years
(C) 52.5 years
(D) none of these

The activity of a radioactive element reduces to (1//16)th of its original value in 30 years. Find its half life?

Find the half-life period of a radioactive material if its activity drops of (1/16)^(th) of its initial value in 40 years.

Radioactive disintegration is a first order reaction and it's rate depends only upon the nature of nucleus and does not depend upon external factors like temoperature an pressure. The rate of radioactive disintigration (Activity) is respresented as (-d(N))/(dt)=lambdaN Where lambda =decay consatant, N= number of nuclei at time t, N""_(0) =initial no. of nucleei. The above equation after integration can be represented as lamda=2.303/tlog.(N""_(0))/(N) Calculate the half-life period of a radioactive element which remains only 1/16 of it's original amount in 4740 years:

The half-life periof of a radioactive substance is x years. The fraction remaining after 2x years is………….. .

A radioactive element reduces to 25% of its initial value in 1000 years. What is half-life of the element ?

Calculate the average life of a radioactive substance whose half life period is 1650 years.

Radioactivity of a radioactive element remains 1//10 of the original radioactivity after 2.303 seconds. The half life period is