`" In a square "ABCD,G_(1)=(3,5),G_(2)=(5,3)" are centroids of "Delta ABC" and "Delta ACD" then area of the square is "`

If G is the centroid of Delta ABC and AG-BC, then /_BGC is :

If G is the centroid of Delta ABC, then bar(CA) + bar(CB) =

Three vertices of a triangle ABC are A(2,1),B(7,1) and C(3,4) . Images of this triangle are taken in x-axis, y-axis and the line y = x . If G_(1),G_(2) and G_(3) are the centroids of the three image triangles then area of triangle G_(1)G_(2)G_(3) is equal to

ABC is a triangle.The coordinates of whose vertices are (-2,4),(10,-2) and (-2,-8).G is the centroid of triangle ABC, then area of the triangle GBC is equal to 26(b)36 (c) 24 (d) 39

ABC is a Delta such A,B,C are at a distance 5 units from the origin. If ((1)/(3)-(1)/(3)) is the centroid of DeltaABC then the orthocentre is

If G is the centriod of Delta ABC and if area of Delta AGB is 5 sq units.Then area of Delta ABC is P sq units then value of P is

Triangle ABC is formed by joining the points of intersection of tangents at points P a and R on the parabola y^(2)=4ax. If G_(1)&G_(2) be centroids of the DABC and DPQR then the slope of G_(1)G_(2) is

Let A(5,6), B(-2,3) and C(6,-1) be the vertices of Delta ABC . Find the coordinates of the centroid of the triangle.