" The velocity of a projectile at point of projection is "`5hat i+4hat j`" its velocity at the point of return to the same horizontal plane is "

The initial velocity of a projectile at the point of projection is 3hat i+4hat j ms^(-1) .Then the velocity of striking on the ground is

The velocity of a projectile at the initial point A is (2hat(i)+3hat(j))m//s .Its velocity (in m//s) at point B is

Velocity of a particle at some instant is v=(3hat i + 4hat j + 5hat k) m//s . Find speed of the particle at this instant.

A projectile is given an initial velocity 3hat i+4hat jm/sec Its maximum height is

What is the length of projection of vec(A)=3hat(i)+4hat(j)+5hat(k) on xy plane ?

Find the value of mu if the points with position vectors hat i - hat j + 3 hat k and 3 hat i + 4 hat j+ mu hat k are equidistant form the plane hat r .(5 hat i + 2 hat j - 7 hat k )+ 8 =0

Points A and B have position vectors (5hat i-2hat j+4hat k) and (hat i+3hat j-7hat k) then find |vec AB|

A point on the line hat r=2hat i+3hat j+4hat k+t(hat i+hat j+hat k) is

A point on the line vec r=2hat i+3hat j+4hat k+t(hat i+hat j+hat k) is

If vec a=4hat i-3hat j and vec b=-2hat i+5hat j are the position vectors of the points A and B respectively find (i) the position vector of the middle point of the bar(AB)