The magnetic moment of `Cr^(n+)` is `3.87BM` .The ratio of number of paired `e^(-)` and unpaired `e^(-)` in `Cr^(n+)` is equal to

Magnetic moment of Cr^(2+) is nearest to

Magnetic moment of M^(x+) is sqrt(24)BM . The number of unpaired electrons in M^(x+) is.

The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is

Spin only magnetic moment of Cr^(x+) is 4.9 BM then x may be

the magnetic moment value of species X is 4.48 B.M fnd out the number of unpaired electrons In X .

The magnetic moment of an ion in its +3 oxidation state is 3.85 BM . The number of unpaired electrons present in the ions is

The magnetic moment of M^(+) (atomic number = 25 is sqt(15) BM .The number of unpaired electron and the value of x respectivekly are

The magnetic moment of a transition metal ion is found to be 4.90 BM. The number of unpaired electrons present in the ion is