A charge q is given to a solid conducting sphere of mass m and is rotating about it's diameter with angular velocity omega .Then ratio of it's magnetic moment to its angular momentum is ..

The ratio of magnetic dipole moment to angular momentum of electron is

A thin uniformring of radius R carrying uniform charge Q and mass M rotates about its axis with angular velocity omega . The ratio of its magnetic moment and angular momentum is:

A disc rotates with angular velocity omega and kinetic energy E . Then its angular momentum

The body is rotating with uniform angular velocity ( omega ) having rotational kinetic energy ( E) . Its angular momentum (L ) is :

A ring of mass m and radius R is being rotated about its axis with angular velocity omega . If a increases then tension in ring

If a uniform solid sphere of diameter 0.2 m and mass 10 kg is rotated about its diameter with an angular velocity of 2 rad/s, then the its angular momentum in kg m^(2)//s will be

A thin disc of radius R has charge Q distributed uniformly on its surface. The disc is rotated about one of its diametric axis with angular velocity omega . The magnetic moment of the arrangement is

A solid cylinder of mass M and radius R rotates about its axis with angular speed omega . Its rotational kinetic energy is