A bus begins to move with an accelaration of ` 1 ms^(-1)` . A man who is `48m` behind the bus starts running at ` 10 ms^(-1)` to catch the bus, the man will be able to catch the bus after .

A bus begins to move with an acceleration of 1 ms^(-1) . A man who is 1 48m behind the bus starts running at 10 ms^(-1) to catch the bus, the man will be able to catch the bus after .

A man is at a distance of 6 m from a bus. The bus begins to move with a constant acceleration of 3 ms^(−2) . In order to catch the bus, the minimum speed with which the man should run towards the bus is

A bus starts moving with acceleration 2 ms^(-2) . A cyclist 96 m behind the nus starts simultaneously towards the bus at a constant speed of 20 m s^(-1) After some time the bus will be left behind. If bus continues moving with the same acceelration, after what time from the begining, the bus will overtake the cyclist ?

A bus starts moving with acceleration 2 ms^-2 . A cyclist 96 m behind the bus starts simultaneously towards the bus at a constant speed of 20 m//s . After what time will he be able to overtake the bus ?

A person is standing at a distance 's' m from a bus. The bus begins to move with cosntant acceleration 'a' m//s^(2) away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is:

A passenger is standing d metres away from a bus. The bus begins to move eith constat acceleration a. To catch the bus the passenger runs at a constant speed (v) towards the bus, What must so that he may catch the bus.

A bus starts moving with acceleration 2m//s^(2) . A cyclist 96 m behind the bus starts moving simultaneously towards the bus a speed of 20 m/s. After what minimum time will he be able to overtake the bus?

A bus starts form rest with an acceleration of 5 m s^(-2) A man who is on a motorcyle, 24 m behind the bust, overtakes, the bus in 2s. If the motorcyclist moves with uniform velocity, find his velocity