`(cos2 0^0+8sin7 0^0sin5 0^0sin1 0^0)/sin^2 80^0` is equal to -

(cos20^(0)+8sin70^(0)sin50^(@)sin10^(0))/(sin^(2)80^(@)) is equal to

(cos 10^0+sin 10^0)/(cos 10^0-sin 10^0) is equal to tan55^0 b. cos 55^0 c.-tan35^0 d. -cot35^0

(2cos 40^0-cos 20^0)/(sin 20^0)=

(sin8^(0)*sin52^(0)*sin68^(@))/(sin24^(0)) is equal to 12-1(1)/(4)

cos25^(0)cos35^(0)-sin10^(0)sin20^(0) ,

Find the least positive value of x in degrees for which tanx=(cos5^0cos20^0+cos35^0cos50^0-sin5^0sin20^0-sin35^0sin50^0)/(sin5^0cos20^0-sin35^0cos50^0+cos5^0sin20^0-cos35^0sin50^0)

Find the least positive x in degree for which tanx=(cos5^0cos20^0+cos35^0cos50^0-sin5^0sin20^0-sin35^0sin50^0)/(sin5^0cos20^0-sin35^0cos50^0+cos5^0sin20^0-cos35^0sin50^0)

sin20^(0)sin40^(0)sin60^(0)sin80^(@)=(3)/(16)

(cos^(2)1^(0)-cos^(2)2^(0))/(2sin3^(0)*sin1^(0)) is equal to

sin(2sin^(-1) 0.8)=