The ends of latusrectum of a parabola are `(6,7),(6,-1)` .Its vertex is

The ends of latusrectum of a parabola are (-3,1) and (1,1) then one of the equation of parabola is:

The extremities of latusrectum of a parabola are (1,1) and (1,-1) . Then the equation of the parabola can be

Distance between an end of a latus-rectum of the parabola y^(2) = 16x and its vertex is

The ends of the latus rectum of the parabola (x-2)^(2)=-6(y+1) are

The two ends of latusrectum of a parabola are the points (3, 6) and (-5, 6). The focus, is

The length of latus rectum of parabola whose whose focus is (-6,6) and vertex is (-2,2) is

L=(1,3),L'=(1,-1) are the end of latus rectum of a parabola. A is the vertex of the parabola then area of Delta ALL' in sq.units is

Area of the triangle formed by the vertex, focus and one end of latusrectum of the parabola (x+2)^(2)=-12(y-1) is