Let `f(x)={[(x-1)^((1)/(2-x)),x>1,x!=2`,`[k,x=2]` .The value of `k` for which `f` is continuous at `x=2` is

The function f(x) = (x-1)^(1/((2-x)) is not defined at x = 2. The value of f(2) so that f is continuous at x = 2 is

If f(x)={{:(,x([(1)/(x)]+[(2)/(x)]+.....+[(n)/(x)]),x ne 0),(,k,x=0):} and n in N . Then the value of k for which f(x) is continuous at x=0 is

let f(x)=[tan((pi)/(4)+x)]^((1)/(x)),x!=0 and f(x)=k,x=0 then the value of k such that f(x) hold continuity at x=0

Let f(x)=(log (1+x+x^2)+log(1-x+x^2))/(sec x-cosx) , x ne 0 .Then the value of f(0) so that f is continuous at x=0 is

For what value of k is the following function continuous at x=2? f(x)={[2x+1,;,x 2]}

If f(x)={[2x+3; if x 1] is continuous at x=1 then k will be

Let f(x)={(x)/(2)-1,0<=x<=1(1)/(2),1<=x<=2}g(x)=(2x+1)(x-k)+3,0<=x<=oo theng(f(x)) is continuous at x=1 if k equal to:

Let f (x) =(2 |x| -1)/(x-3) Range of the values of 'k' for which f (x) = k has exactly two distinct solutions:

Let f(x) = {((x^(2) -2x -3)/(x + 1)","," when " x != -1),(" k,"," when " x = -1):} If f(x) is continuous at x = -1 then k = ?

If f(x)={x^(2)sin((1)/(x^(2))),x!=0,k,x=0 is continuous at x=0, then the value of k is