A(0,5) and B(0,-5) are the points and |AP-PB|=8 then the locus of P is `a x^2+by^2+c= 0` then |a+b+c|=

A(5,0) and B(-5,0) are two points PA =3PB Then locus of P is a circle with radius r then 4r^2=

If A=(0,4),B=(0,-4) and |PA-PB|=6 and the locus of P is 7y^(2)-9x^(2)=9k ,Then k is

A(-9,0),B(-1,0) are two points.If P is a point such that PA:PB=3:1, then the locus of P is

A(0,4),B(0,-4) are two points.The locus of P which moves such that |PA-PB|=6 is

Given the points A(0,4) and B(0,-4), the equation of the locus of the point P(x,y) such th |AP-BP|=6 is

Given the points A(0,4) and B(0,4). Then the equation of the locus of the point P(x,y) such that |AP-BP|=6, is

If A(5,0) and A(-5,0) be the points then find its equation of locus of all e moving points such that |AP-A^(1)P|=8. hence trace and idente fey its locus.

A(4,0) , B(-4,0) are two points.If the locus of P which moves such that |PA-PB|=6 is ax^(2)+by^(2)-63=0 .Then |a+b| is equal to

The distances of a point 'P' from the points A(5,-4),B(7,6) are in the ratio 2:3 and the locus of P is x^(2)+y^(2)-(34)/(5)x+(120)/(5)y+k=0 then "k" is