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tan^-1[[2cosx-3sinx]/[3cosx+2sinx]]...

`tan^-1[[2cosx-3sinx]/[3cosx+2sinx]]`

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Find- tan^-1[(cosx-sinx)/(cosx+sinx)]

Find dy/dx , if y=tan^-1((cosx-sinx)/(cosx+sinx))

Solve: tan^(-1)((cosx-sinx)/(cosx+sinx))

int((2cosx-3sinx)/(3cosx+2sinx))dx

Find the derivative of tan^(-1)((cosx - sinx)/(cosx + sinx)) with respect to 'x'

Find dy/dx , tan^(-1){(cosx - sinx)/(cosx + sinx)} .

Show that tan^(-1)[(cosx+sinx)/(cosx-sinx)]=(pi)/(4)+x .

tan^(-1) ((cosx - sinx)/(cosx + sinx)) , 0< x < pi