If `1,1,alpha` are the roots of `x^3-6x^3+9x-4=0` then `alpha=`

If 1,1,alpha are the roots of x^3 -6x^2 +9 x-4=0 then find ' alpha'

if 1,1, alpha are the roots of x^3-xx^2+9x-4=0 ,then find alpha .

If 1,1, alpha are the roots of x ^(3) -6x ^(2) + 9x- 4 =0 then find 'alpha '.

If -1,2 and alpha are the roots of 2x^3 +x^2-7x-6=0 , then find alpha

If -1,2 and alpha are the roots of 2x^3 +x^2-7x-6=0 , then find alpha

If alpha , beta , gamma are the roots of x^3 -6x -4=0 then the equation whose roots are (beta gamma +(1)/( alpha)) ,(gamma alpha +(1)/(beta)) , (alpha beta +(1)/( gamma)) is

If -1, 2 , alpha are roots of 2x^(3) + x^(2) - 7x - 6 = 0 then alpha =

If alpha,beta, gamma are the roots of 4x^(3) - 6x^(2) + 7x + 3 = 0 then alpha beta + alpha beta + alpha gamma =

If alpha,beta,gamma are the roots of x^(3)-9x^(2)+26x-24=0 then sum(alpha+3)(beta+3)=