f(x)=((x^(a))/(x^(b)))^(a+b)((x^(b))/(x^(c)))^(b+c)((x^(c))/(x^(a)))^(c+a)

If f(x)=((x^(2))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a), then f'(x) is equal to: (a) 1(b)0(c)x^(a+b+c) (d) None of these

If y = ((x^(a))/(x^(b)))^(a + b) ((x^(b))/(x^(c)))^(b + c) ((x^(c))/(x^(a)))^(c + a) , "then" (dy)/(dx) is equal to

((x^(a))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a)=? a.0 b.x^(abc) c.x^(a+b+c)d.1=? a.0

Differentiate ((x^(a))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a) with respect to x.

Prove that :((x^(a))/(x^(b)))^(a+b-c)((x^(b))/(x^(c)))^(b+c-a)((x^(c))/(x^(a)))^(c+a-b)=1

Simplify: ((x^(a))/(x^(-b)))^(a-b)xx((x^(b))/(x^(-c)))^(b-c)xx((x^(c))/(x^(-a)))^(c-a)

The value of ((x^(a))/(x^(b)))^(a+b) xx ((x^(b))/(x^(c)))^(b+c) xx ((x^(c))/(x^(a)))^(c + a) is equal to

If y = (x^(a)/(x^(b)))^(a+b) .(x^(b)/(x^(c)))^(b+c) .(x^(c)/(x^(a)))^(c+a) then, dy/dx =

Prove that: ((x^(a))/(x^(b)))^(c)x((x^(b))/(x^(c)))^(a)x((x^(c))/(x^(a)))^(b)=1

Simplify: ((x^(b))/(x^(c)))^(a)xx((x^(c))/(x^(a)))^(b)xx((x^(a))/(x^(b)))^(c)