" 16."2x-3y+6=0,2x+3y-18=0

Solve the following system of equations graphically: 2x-3y+6=0,quad 2x+3y-18=0 Also, find the area of the region bounded by these two lines and y-axis.

Draw the graphs of the following equations: 2x-3y+6=0,\ \ \ 2x+3y-18=0,\ \ \ y-2=0 Find the vertices of the triangle so obtained. Also, find the area of the triangle.

Solve the following system of equations graphically: 2x-3y+6=0,\ \ \ 2x+3y-18=0 Also, find the area of the region bounded by these two lines and y-axis.

Area of triangle formed by straight lines 2x - 3y + 6 =0, 2x + 3y - 18 = 0 and y -1 = 0 is

The area (in sq units) of the quardilateral formed by the lines 2x + 3y + 6 = 0, 2x - 3y + 6 = 0, 2x + 3y - 6 = 0 and 2x - 3y - 6 = 0 is

If the co-ordinates of A and B are (1,1)and (5,7), then the equation of the perpendicular bisector of the line segment AB is............... A) 2x+3y=18 B) 2x-3y+18=0 C) 2x+3y-1=0 D) 3x-2y+1=0

The lines represented by 2x+3y-9 =0 and 4x+6y-18=0 are

If 2x+3y-6=0 and 9x+6y-18=0 cuts the axes in concyclic points, then the centre of the circle, is

Find the point of intersection of the straight lines : (i) 2x+3y-6=0 , 3x-2y-6=0 (ii) x=0 , 2x-y+3=0 (iii) (x)/(3)-(y)/(4)=0 , (x)/(2)+(y)/(3)=1