" (v) "x^(8)-y^(8)

Factorizing the difference of squares: (i)x^(8)-y^(8)(ii)a^(12)x^(4)-a^(4)x^(12)

Factorise : x^(8)-y^(8)

The HCF of (x^(4) - y^(4)) and (x^(8) - y^(8)) is:

(x-y)(x+y)(x^(2)+y^(2))(x^(4)+y^(4)) is equal ot: x^(16)-y^(16)(b)x^(8)-y^(8)x^(8)+y^(8)(d)x^(16)+y^(16)

Given (x^(2)+y^(2))/(x^(2)-y^(2))+(x^(2)-y^(2))/(x^(2)+y^(2))=k then (x^(8)+y^(8))/(x^(8)-y^(8)) in terms of k is equal to

Factorize each of the following algebraic expressions : x^(8)-y^(8)( ii) a^(12)x^(4)-a^(4)x^(12)

Factorise x^(8)-y^(8)

Factorize each of the following algebraic expressions : (i) x^8-y^8 (ii) a^(12)x^4-a^4x^(12)

Factorize: (i)9-a^6+2a^3b^3-b^6 (ii)x^(16)-y^(16)+x^8+y^8