[x-3y=7],[3x-3y=15]

Which of the following pairs of linear equations has unique solution,no solution,or infinitely many solutions.In each there is unique solution ,find it by using cross multiplication method.(iv)3x-3y-7=0 3x-3y-15=0

Which of the following pairs of linear equations has a unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross-multiplication method: x-3y-7=0 3x-3y-15=0

Which of the followings pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x-3y-7=0 3x-3y-15=0

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. : - x-3y-7=0 , 3x-3y-15=0

Solve frac[dx][dy]=frac[3x-7y+7][3y-7x-3]

If [[x+y,-7],[3,x-y]]=[[3,-7],[3,-1]] then (x,y) is

solve for x and y - 2x+3y=7 3x-4y=2

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x- 3y-7=0 3x- 3y- 15= 0

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solution, no solution, or ininitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x-3y-7=0 and 3x-3y-15=0

If x+y=7,xy=15 then x^(3)+y^(3)=