Let `T_(1)` and `T_(2)` be the time periods of two springs A and B when a mass m is suspnded from them seperately. Now both the springs are connected in parallel and same mass m is suspended with them. Now let T be the time period in this position. Then -

Options

A. `T=T_(1)+T_(2)`
B. `T=(T_(1)T_(2))/(T_(1)+T_(2))`
C. `T^(2)=T_(1)^(2)+T_(2)^(2)`
D. `1/T^(2)=1/T_(1)^(2)+1/T_(2)^(2)`

Answer

4

Explanation

`T_(1)=2pisqrt(m/k_(1))rArrk_(1)=(4pi^(2)m)/(T_(1)^(2))`
`T_(2)=2pisqrt(m/k_(2))rArrk_(2)=(4pi^(2)m)/(T_(2)^(2))`
Now `T=2pisqrt(M/k) k=(4pi^(2)m)/(T^(2))`
in parallel k=`K_(1)+k_(2)`