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IF the de-Brogile wavelength of a proton...

IF the de-Brogile wavelength of a proton is `10^(-13)m`, the electric potential through which it must have been accelerated is

A

`4.07xx10^(4)V`

B

`8.15xx10^(4)V`

C

`8.15xx10^(3)V`

D

`4.07xx10^(5)V`

Text Solution

Verified by Experts

The correct Answer is:
2
`lamda_(p)=0.286/sqrtV`
`lamda_(p)=10^(-13)m=10^(-3)Å`
`10^(-3)=0.286/sqrtV`
`rArrV=(0.286)^(2)xx10^(6)`
`=0.0817xx10^(6)`
`rArr8.15xx10^(4)` volt
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