The count rate observed from a radioactive source at `t` sound was `N_0` and at `4t` second it was `(N_0)/(16)`. The count rate observed at `(11/2)t` second will be

Options

A. `N_(0)/128`
B. `N_(0)/64`
C. `N_(0)/32`
D. None of these

Answer

2

Explanation

`N_(0)overset(3t)toN_(0)/16`
`t=0 t=t t=4t`
`A=A_(0)C^(-lamdat)`
`N_(0)/16=N_(a)c^(-lamda(3t))`
`c^(3lamdat)`
`N_(0)overset(9t//2)toN=?`
t=t `t=11/2t`
`A=A_(0)c^(-lamdat)`
`N=N_(0)e^((9t)/2lamda)`
`N=N_(o)(e^(-3lamdat))^(3//2)`
`N=N_(0)(1/16)^(3//2)`
`N=N^(0)/64`