In the figure given below, the end B of the rod AB which makes angle `theta` with the floor is pulled with a constant velocity `v_(0)` as shown. The length of rod is l. At an instant when `theta=37^(@)`

Options

A. Velocity of end A is `(4v_(0))/3`
B. angular velocity of rod is `(5v_(0))/(6l)`
C. angular velocity of rod is constant
D. velocity of end a is constant

Answer

1

Explanation

`x^(2)+y^(2)=l^(2)`
`rArr(dy)/(dt)=-(x/y)(dx)/(dt)`
`thereforev_(A)=-4/3v_(0)`
Now, x=l`costheta`
`(dx)/(dt)=-lsintheta(d theta)/(dt)rArromega=-5/3(v_(0)/l)`