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A particle is projected from a point A w...

A particle is projected from a point A with velocity `usqrt2` at an angle of `45^(@)` with horizontal as shown in the figure. It strikes the plane BC at right angles. The velocity of the particle at the time of collision is

A

`(sqrt3u)/2`

B

`u/2`

C

`(2u)/sqrt3`

D

None

Text Solution

Verified by Experts

The correct Answer is:
3

Let v be the velocity at the time of collision.
Then, `usqrt2cos45^(@)=vsin60^(@)`

`(usqrt2)(1/sqrt2)=(sqrt3v)/2`
`therefore v=2/sqrt3u`
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