A particle is moving along a straight line. Its displacement-time graph is shown

`{:(,,"Column-I",,"Column-II"),(,(A),"Work done on particle from 0 to "t_(1),(P),"Positive"),(,(B),"Work done on particle from " t_(1) " to " t_(2),(Q),"Negative"),(,(C),"Work done on particle from " t_(2) " to " t_(3),(R),"zero"),(,(D),"Work done on particle from " t_(3) " to " t_(4),(S),"Unpredectible"):}`

Options

A. `AtoR,BtoR,CtoP,DtoQ`
B. `AtoS,BtoR,CtoP,DtoQ`
C. `AtoR,BtoS,CtoP,DtoQ`
D. `AtoR,BtoR,CtoQ,DtoP`

Answer

1

Explanation

For 0`gttgtt_(0)to`slope=constnt
W=0
For `t_(1)lttltt_(2)to`slope=0
W=0
For `t_(2)lttltt_(3)to` slope is increasing
W=+ve
For `t_(3)lttltt_(4)to` slope is decreasing
W=-ve