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What will be the temperature at which a ...

What will be the temperature at which a solution containing 6 g of glucose per 1000 g water with boil, if molal elevation constant for water is 0.52/1000 g.

A

`1000.173^(@)`C

B

`100.0173^(@)`C

C

`100.173^(@)`C

D

None

Text Solution

Verified by Experts

The correct Answer is:
2
w=6g, W=1000g, Mol. wt. of glucose= 180
`DeltaT_(b)=(1000xxK_(b)xxw)/(180xx1000)=0.0173^(@)C`
Hence boiling point of solution =b.p of water +
`DeltaT_(b)=100+0.0173^(@)C`
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