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Plotting a graph of log t(1//2) against ...

Plotting a graph of log `t_(1//2)` against log `[A]_(0)` of a rectant for a first order reaction, the slope will

A

`-1`

B

`-2`

C

0

D

`+1`

Text Solution

Verified by Experts

The correct Answer is:
3
`t_(1//2)=0.693/K`
`logt_(1//2)=log0.693-log K=`consatnt
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