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In an A.P the sum of the first n terms b...

In an A.P the sum of the first n terms bears a constant ratio `lamda` with the sum of the next n terms then `lamda` =

A

`1/2`

B

`1/3`

C

`1/4`

D

`2/5`

Text Solution

Verified by Experts

The correct Answer is:
2
a,a + d,a+ 2d……… in A.P
`lambda=("the sum of hte first n terms")/("the sum of the next n terms")`
`=((n)/(2)[2a + (n -1)d])/((n)/(2) [(2(a +nd)+(n-1)d)]]= (2a-d+nd)/( 2a-d+3nd)`
`=(1)/(3)` if `d=2a`
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