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Circumradius of a Delta ABC is 2, O is t...

Circumradius of a `Delta ABC` is 2, O is the circumcentre, H is the orthocentre then- `1/64(AH^2+BC^2)(BH^2+AC^2)(CH^2+AB^2)` is equal to

A

64

B

16

C

`1/64`

D

1

Text Solution

Verified by Experts

The correct Answer is:
1
`AH^(2)+BC^(2)=4R^(2)cos^(2)A+4Rsin^(2)A=4R^(2)`
`rArr1/64(AH^(2)+BC^(2))(BH^(2)+AC^(2))(CH^(2)+AB^(2))`
`(64R^(6))/64=R^(6)=64`
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