A scylindrical rod of mass M, length L & radius R has cords wound around it , whose ends are attached to the ceioling .The rod is held borizontal and released .The liinear acceleration of the cylinder as it falls and tension in the cords is

Options

A. `g,Mg//2`
B. `g//3,Mg//3`
C. `2g//3,Mg//6`
D. `g//2,Mg//12`

Answer

3

Explanation

Mg-2T=Ma
`T.r+t.r =1 alpha`
`2T=(ma)/(2)`
`{I=(Mr6(2))/(2),alpha=(a)/(r )}`
so `a = (2g)/(3)`
`T=(Mg)/(6)`