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A body o fmass 6 kg moves in a staight l...

A body o fmass 6 kg moves in a staight line according to the equation x=`t^(3)-75t`, where x denotes the distance in metre and t the time in second. The force on the body at t=4s is

A

64 N

B

72 N

C

144 N

D

36 N

Text Solution

Verified by Experts

The correct Answer is:
3
`V=(dx)/(dt)=3t^(2)-75`
`a=(dv)/(dt)=6t,a_(1)-4=24`
`F=ma`
`=6(24)`
`=144 N`
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