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The equation of the hyperbola whose foci...

The equation of the hyperbola whose foci are (6.5), (-4,5) and eccentricity 5/4 is

A

`(x-1)^(2)/(16)-(y-5)^(2)/(9)=1`

B

`(x)^(2)/(16)-(y)^(2)/(9)=1`

C

`(x-1)^(2)/(16)+(y-5)^(2)/(9)=1`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
1

`ae=5`
`axx(5)/(4)=5`
`a=4`
`b^(2)=16 ((25)/(16)-1)`
`b^(2)=9`
`(x-1)^(2)/(16)-(y-5)^(2)/(9)=1`
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