Through the centriod of an equilateral triangle a line parallel to the base is drawn. On this line, an arbitary point P is taken inside the triangle. Let h denote the distahce of P from the base of the triangle. Let `h_(1) and h_(2)` be the distance of P from the other two sides of the triangle, then

Options

A. h is the H.M of `h_(1), h_(2)`
B. h is the G.M of `h_(1), h_(2)`
C. h is the A.M of `h_(1), h_(2)`
D. None of these

Answer

3

Explanation

`Delta ABC = Delta PAB +Delta PBC + DeltaPAC`
`(1)/(2)xxaxx(3h)=(1)/(2)ah_(1)+(1)/(2)ah+(1)/(2)ah_(2)`
`rArr h = (h_(1)+h_(2))/(2)`