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The system of equation |z+2-2i|=4 and |...

The system of equation `|z+2-2i|=4 and |z|=1 has -

A

Two solutions

B

No solution

C

Infinite solutions

D

One solution

Text Solution

Verified by Experts

The correct Answer is:
2
`If |z| =1`
`center = (0,0), radius =1`
`If |z-(-2+2i)|=4`
`center = (-2),2), radius =4`

Both the circles are not interesect to each other so , o solution
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