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A nucleus X initially at rest, undergoes...

A nucleus X initially at rest, undergoes alpha decay according to the equation
`._Z^232Xrarr_90^AY+alpha`
What fraction of the total energy released in the decay will be the kinetic energy of the alpha particle?

A

`(90)/(92)`

B

`(228)/(232)`

C

`sqrt((228)/(232))`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
2
`k_(a)=(A-4)/(A)Q`
Fraction `(K_(a))/(Q)=(A-4)/(A)`
=`(232-4)/(232)`
=`(228)/(232)`
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