A solution containing 500 g of a protein per liter is isotonic with a solution containing 3.42 g sucrose per liter. The molecular mass of protein in 5 x `10^(x)`, hence x is.

Options

A. 2
B. 3
C. 4
D. 5

Answer

3

Explanation

`pi1=pi2`
`C_(1)=C_(2)`
`((w_(1))/(m_(1)v_(1)))_("protein")=((w_(2))/(m_(2)v_(2)))_("sucrose")`
`(500)/(5xx10^(x)xx1)=(3.42)/(342xx1)`
`(100)/(10^(x))=(1)/(100)`
`10^(x)=10^(4)`
x= 4