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The solubility in terms of K(sp) "for " ...

The solubility in terms of `K_(sp) "for " A_3B_((aq))` is

A

`((K_(SP))/(3))^((1)/(4))`

B

`((K_(SP))/(27))^((1)/(4))`

C

`(27K_(SP))^((1)/(4))`

D

`(3K_(SP))^((1)/(4))`

Text Solution

Verified by Experts

The correct Answer is:
2
`A_(3)B_(aq)hArrunderset("3S")underset()(3A^(+))+underset(S)underset()(B^(3))-`
`K_("sp")=27s^(3)xxs`
`s=((K_("sp"))/(27))^(1/4)`
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