A particle of mass `m` is made to move with uniform speed `v_(0)` along the perimeter of a regular hexagon inscribed in a circle of radius `R`. The magnitude of impulse applied at each corner of the hexagon is :-

Options

A. `2mv_(0) sin. pi/6`
B. `mv_(0)sin. pi/6`
C. `mv_(0) sin. pi/3`
D. `2mv_(0) sin. pi/3`

Answer

A

Explanation

I=change in momentum
`=sqrt((mv_(0))^(2)+(mv_(0))^(2)-2(mv_(0))^(2)-2(mv_(0))^(2) cos 60^(@))`
`=mv_(0)sqrt(2-2 cos(pi//3))= mv_(0) sin. pi/6`