The moment of inertia of a solid flywheel about its axis is `0.1 kg-m^(2)`.A tangential force of 2 kg-wt. is applied round the circumference of the flywheel with the help of a string and mass arrangement as shown in the figure. If the radius of the wheel is 0.1 m, find the acceleration `("in rad/sec"^(2))` of the mass :

Options

A. 163.3
B. 16.3
C. 81.66
D. 8.16

Answer

B

Explanation

`a=(m"g")/(m+I//r^(2))=(19.6)/12`
`alpha=a/R="16.33 "rad//s^(2)`