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An iron rod of length L and magnetic mom...

An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be

A

M

B

`(2M)/(pi)`

C

`(M)/(pi)`

D

`Mpi`

Text Solution

Verified by Experts

The correct Answer is:
B

`M' = (2R) m = (2ml)/(pi) = (2M)/(pi)`
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