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One 10V, 60W bulb is to be connected to ...

One `10V, 60W` bulb is to be connected to `100V` line. The required inductance coil has self-inductance of value `(f=50Hz)`

A

0.052 H

B

2.42 H

C

16.2 mH

D

1.62 mH

Text Solution

Verified by Experts

The correct Answer is:
A

`R = (V_(R)^(2))/(P_(R))`
`V_(R)I_(R) = P_(R)`
`I_(R) = (P_(R))/(V_(R)) = (P_(S))/(Z) rArr Z = (100)/((60)/(10)) = (100)/(6)`
`sqrt(R^(2) + X_(L)^(2)) = ((100)/(6))^(2)`
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