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Prove that the function f(x)=tanx-4x is ...

Prove that the function `f(x)=tanx-4x` is strictly decreasing on `(-pi//3,\ pi//3)` .

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We have to proof that the function `f(x)=tanx-4x` is strictly decreasing on `(-pi/3,\ pi/3)` `f(x)=tanx−4x`
`impliesf'(x)=sec^2x−4`
When
`(−pi/3`<`x`<`pi/3)`,`(1`<`secx`<`2)`
Therefore,
`1`<`sec^2x`<`4implies−3`<`(sec^2x−4)`<`0`
...
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