" If "n" is a natural number,then "[[2-1],[3-2]]^(pi)=

If n is a natural number. Then {:[(2,-1),(3,-2)]^n:} , is

If n is a natural number. Then {:[(2,-1),(3,-2)]^n:} , is

If n is any natural number, then 5^(2n)-1 is always divisible by how many natural numbers ?

The set (0,2,6,12,20) in the set-builder form is (1) {x:x=n^(2)-3n+2," where "n'" is a natural number "&1 (2) {x:x=n^(2)-3n+2," where "'n'" is a natural number "&1 (3) {x:x=n^(2)-3n+4," where "'n'" is a natural number "&1 (4) {x:x=n^(2)+5n-6," where 'n' is a natural number "&1<=n<=5}

If n is a natural number then show that 1.3.5.7…..(2n-1) = ((2n)!)/(2^n n!)

If A={4n+2|n " is a natural number"} and B={3n|n " is a natural number"} , then what is (AnnB) equal to?

If n is a natural number then show that n! + (n+1)! = (n+2)n!

If n is natural number & n ge 1, then (3^(2n) - 1) is always divisible by

If n is a natural number gt 2 , such that z^(n) = (z+1)^(n) , then

If n is a natural number, then which of the following is not always divisible by 2? 1.) n^2-n 2.) n^3-n 3.) n^2-1 4.) n^3-n^2