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Bacteria multiply at a rate proportional to the number present. If the original number N double in 3 hours, the number of the bacteria will be 4N is (in hours).

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To solve the problem where bacteria multiply at a rate proportional to the number present, we can follow these steps: ### Step 1: Set up the differential equation Given that the rate of growth of bacteria is proportional to the number present, we can express this mathematically as: \[ \frac{dN}{dt} = \lambda N \] where \( \lambda \) is a constant. ...
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RD SHARMA-DIFFERENTIAL EQUATION-Solved Examples And Exercises
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  7. Solve: (dy)/(dx)=1/(sin^4x+cos^4x)

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  8. Solve the initial value problem e^((dy//dx))=x+1; y(0)=5.

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  9. Solve the following initial value problems: (22-26) sin((dy)/(dx))=k ...

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  10. Solve the initial value problem e^((dy//dx))=x+1; y(0)=5.

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  11. Solve the following initial value problems: (22-26) x(x^2-1)("dy")/("...

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  12. Solve: 1.(x+1)(dy)/(dx)=2x y 2.cosx(1+cosy)dx-s in y(1+sinx)dy=0

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  13. Solve the following differential equations: y-x(dy)/(dx)=a(y^2+(dy)...

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  14. Solve: log((dy)/(dx))=a x+b y

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  15. Solve the initial value problem y^(prime)=ycot2x ,y(pi/4)=2.

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  16. if a,b are two positive numbers such that f(a+x)=b+[b^3+1-3b^2f(x)+3b...

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  17. Solve the initial value problem: dy=e^(2x+y)dx ,y(0)=0.

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  18. Solve the initial value problem: x(xdy+ydx)=ydx ,y(1)=1.

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  19. Solve: (dy)/(dx)=ysin2x it being given that y(0)=1.

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  20. Solve the initial value problem: (xdy+ydx)=xy dx ,y(1)=1.

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