Water at temperature `100^@C` cools in 10 minutes to `88^@C` in a room of temperature `25^@C`. Find The temperature of water after 20 minutes

Explanation

To solve the problem step by step, we will use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its own temperature and the ambient temperature.

### Step 1: Set up the differential equation
According to Newton's Law of Cooling, we have:
\[ \frac{dT}{dt} = -\lambda (T - T_a) \]
where:
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