The value of alternating emf E in the given circuit will be VR=80V Vc=100V w www HF KV =4012 E,50 Hz

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and frequency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and freqency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 Omega and L = 800 mH, the peak value of current will be in ampere :

The peak value of an alternating emf E given by E = underset(o)(E) cos omega t is 10 V and frequency is 50 Hz . At time t = (1/600) s, the instantaneous value of emf is

The value of alternating e.m.f. is e = 500 sin 100pit , then the frequency of this potential in Hz is –

The rms values of the terminal potential differences of R ,L and C of a series circuit are 80V ,70V and 10V respectively.What is the rms value of the applied emf in the circuit?

An alternating e.m.f. of peak value 110 V andfrequency 50 Hz is connected across LCR series circuit with R = 100 Omega , L = 10 mH, C = 25 muF . Calculate the inductive reactance, capacitive reactance and impedance.

Determine the voltage drop across the resistor R_1 in the circuit given below with E = 65V, R_1 = 50 OmegaR_2 = 100 Omega, R_3 = 100 Omega, and R_4 300 Omega.

An inductance of 0.4/(pi) henry and a resistace of 30 Omega are joined in series. If an alternating e.m.f. of 200 V, 50 Hz is applied to their combination, then the impedance of the circuit will be