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In a reaction, 5.3 g of sodium carbonate...

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
sodium carbonate + acetic acid `→` sodium acetate + carbon dioxide + water

Text Solution

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In a reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbondioxide, and water.
Sodium Carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water
Mass of sodium carbonate = 5.3g (Given)
Mass of ethanoic acid = 6g (Given)
Mass of sodium ethanoate = 8.2g (Given) Mass of carbon dioxide = 2.2 (Given)
Mass of water = 0.9g (Given)
Now, total mass before the reaction = (5.3 + 6)g
= 11. 3g
And total mass after the reaction = (8.2 + 2.2 + 0.9)g
= 11.3g
Therefore, Total mass before the reaction = Total mass after the reaction
Hence, the given observations are in agreement with the law of conservation of mass.
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In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass. Sodium carbonate + ethanoic acid to sodium ethanoate + carbon dioxide + water

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Knowledge Check

  • In a reaction 6.0g of sodium carbonate were reacted with 10g of hydrochloric acid solution. The product was a mixture of 4.5g of carbon dioxide and 11.5g of sodium chloride solution. This data in agreement with the law of

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  • The reagent that reacts with acetic acid to give sodium acetate with liberation of carbon dioxide gas is

    A
    sodium metal
    B
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    C
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    D
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  • When a buffer solution of sodium acetate and acetic acid is diluted with water, then pH

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