Two objects of masses `100g` and `200g` are moving along the same line in the same direction with velocities of `2m//s` and `1m//s`, respectively. They collide and after the collison, the first object moves at a velocity of `1.67 m//s` in the same direction. Determine the velocity of the second object.

Explanation

Mass of one of the objects, `m_(1) = 100 g = 0.1 kg `
Mass of the other object, `m_(2) = 200 g = 0.2 kg `
Velocity of `m_(1)` before collision, `v_(1) = 2 m//s`
Velocity of `m_(2)` before collision, `v_(2) = 1 m//s`
Velocity of` m_(1)` after collision, `v_(3) = 1.67 m//s`
Velocity of `m_(2)` after collision `= v_(4)`
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore ` m_(1)v_(1) + m_(2)v_(2) = m_(1)v_(3) + m_(2)v_(4) `
` 2(0.1)+1(0.2)=1.67(0.1)+v_(4)(0.2)`
` 0.4 = 0.67 + 0.2v_(4)`
` v_(4) = 1.165` m/s
Hence, the velocity of the second object becomes 1.165 m/s after the collision