A force of 5 N is acting on an object. The object is displaced through 2 m in the direction of the force (Fig. 11.2). If the force acts on the object all through the displacement, then work done is `5 N xx 2 m =10 N` m or `10 J`.

Explanation

Given that:

Force applied, `F=5N`

displacement, `d=2m`

we know that

work done, `W=F*d`

`W=Fdcostheta`

here `theta=0`(since force and displacement are acting in same direction)

`W=Fdcos0`

...