A submarine emits a sonar pulse, which returns from an underwater cliff in `1.02 s`. If the speed of sound in water is `1531 m//s`, how far away is the cliff ?

Explanation

Time taken by the sonar pulse to return, t = 1.02 s
Speed of sound in salt water, v = 1531 ms - 1
Distance of the cliff from the submarine = Speed of sound `xx` Time taken
Distance of the cliff from the submarine = 1.02 `xx` 1531 = 1561.62 m
Distance travelled by the sonar pulse during its transmission and reception in water = 2 `xx` Actual distance = 2d
Actual Distance, d= Distance of the cliff from the submarine/2
= 1561/2
= 780.31 m