Which of the statements about the reaction below are incorrect ?
`2PbO(s) + C(s) rarr 2Pb(s) + CO_(2)(g)`
(a) Lead is getting reduced.
(b) Carbon dioxide is getting oxidised.
(c) Carbon is getting oxidised.
(d) Lead oxide is getting reduced.

Options

A. `(a)` and `(b)`
B. `(a)` and `(c)`
C. `(a), (b)` and `(c)`
D. all

Explanation

To determine which statements about the reaction `2PbO(s) + C(s) → 2Pb(s) + CO₂(g)` are incorrect, we need to analyze the oxidation and reduction processes involved in this reaction.

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- Reactants: Lead(II) oxide (PbO) and Carbon (C)
- Products: Lead (Pb) and Carbon dioxide (CO₂)

2. **Determine Oxidation States:**
- In PbO, lead (Pb) has an oxidation state of +2 and oxygen (O) has an oxidation state of -2.
- In elemental carbon (C), the oxidation state is 0.
- In the product lead (Pb), the oxidation state is 0.
- In carbon dioxide (CO₂), carbon (C) has an oxidation state of +4 and oxygen (O) remains -2.

3. **Analyze Changes in Oxidation States:**
- Lead (from PbO) goes from +2 (in PbO) to 0 (in Pb), indicating a reduction (gain of electrons).
- Carbon goes from 0 (in C) to +4 (in CO₂), indicating an oxidation (loss of electrons).

4. **Evaluate Each Statement:**
- (a) **Lead is getting reduced.**
- Incorrect. Lead is produced (Pb) from PbO, but it is the PbO that is being reduced, not lead itself.
- (b) **Carbon dioxide is getting oxidized.**
- Incorrect. Carbon dioxide is a product and does not undergo oxidation in this reaction.
- (c) **Carbon is getting oxidized.**
- Correct. Carbon is oxidized to form CO₂.
- (d) **Lead oxide is getting reduced.**
- Correct. PbO is reduced to Pb.

5. **Conclusion:**
- The incorrect statements are (a) and (b).

### Final Answer:
The incorrect statements are:
- (a) Lead is getting reduced.
- (b) Carbon dioxide is getting oxidized.