How is the concentration of hydroxide ions` (OH^(–))` affected when excess base is dissolved in a solution of sodium hydroxide?

Explanation

To determine how the concentration of hydroxide ions (OH⁻) is affected when excess base is dissolved in a solution of sodium hydroxide (NaOH), we can follow these steps:

### Step 1: Understand the Components of the Solution
Sodium hydroxide (NaOH) is a strong base that dissociates completely in water to produce sodium ions (Na⁺) and hydroxide ions (OH⁻). The dissociation can be represented as:
\[ \text{NaOH} \rightarrow \text{Na}^+ + \text{OH}^- \]

### Step 2: Identify the Effect of Adding Excess Base
When an excess base is added to the NaOH solution, we need to consider what this excess base is. If we assume the excess base is also a strong base (like KOH, Ca(OH)₂, etc.), it will also dissociate completely in water to produce additional hydroxide ions (OH⁻).
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